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48-6x^2+98x=9x-4+8
We move all terms to the left:
48-6x^2+98x-(9x-4+8)=0
We add all the numbers together, and all the variables
-6x^2+98x-(9x+4)+48=0
We get rid of parentheses
-6x^2+98x-9x-4+48=0
We add all the numbers together, and all the variables
-6x^2+89x+44=0
a = -6; b = 89; c = +44;
Δ = b2-4ac
Δ = 892-4·(-6)·44
Δ = 8977
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(89)-\sqrt{8977}}{2*-6}=\frac{-89-\sqrt{8977}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(89)+\sqrt{8977}}{2*-6}=\frac{-89+\sqrt{8977}}{-12} $
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